m^2-7m+5=0

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Solution for m^2-7m+5=0 equation: 



m^2-7m+5=0

a = 1; b = -7; c = +5;
Δ = b2-4ac
Δ = -72-4·1·5
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{29}}{2*1}=\frac{7-\sqrt{29}}{2}
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{29}}{2*1}=\frac{7+\sqrt{29}}{2}
$

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